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[Matematika] Re: Gausova kriva-pokazati da je konstantna

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Mislim (jer je nama profesor zapisao u drugacijem obliku) da jeste. Naime, mi smo ucili: *Teorema [Egregium, Gaus].* Neka je [tex]r[/tex] regularna povrs u [tex]\textbf{R}^3[/tex]. Tada vazi: [tex]K=\frac{1}{g_{11}g_{22}-g_{12}^2}\left(\sum_{k,l=1}^{2}(\Gamma_{12}^{k}\Gamma_{12}^{l}-\Gamma_{11}^{k}\Gamma_{22}^{l})g_{kl}+\frac{\partial^2 g_{12}}{\partial u_1 \partial u_2} - \frac{1}{2}\frac{\partial^2 g_{11}}{\partial u_2 \partial u_2} - \frac{1}{2} \frac{\partial^2 g_...

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